What is factor 25y^2+40y+16 ?

The solution to factor 25y^2+40y+16 is (5y+4)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 25y^2+40y+16

factor

25 y^{2} + 40 y + 16

(5 y + 4)^{2}

Solution steps

25 y^{2} + 40 y + 16

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 y^{2} = (5 y)^{2}

16 = 4^{2}

40 y = 2 \cdot 5 y \cdot 4

= (5 y)^{2} + 2 \cdot 5 y \cdot 4 + 4^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(5 y)^{2} + 2 \cdot 5 y \cdot 4 + 4^{2} = (5 y + 4)^{2}

= (5 y + 4)^{2}

12 x^{2} + 4 x - 5

544

s^{2} - 9

\frac{( 0 + 4 i ) ( 8 + 4 i )}{6 + 4 i}

∣ 4 x + 8 ∣ - 1 = 10