What are the solutions to the equation 5x^2+12x+4=0 ?

The solutions to the equation 5x^2+12x+4=0 are x=-2/5 ,x=-2

Find the zeros of 5x^2+12x+4=0

The zeros of 5x^2+12x+4=0 are x=-2/5 ,x=-2

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5 x^{2} + 12 x + 4 = 0

x = - \frac{2}{5}, x = - 2

Decimal Notation

x = - 0.4, x = - 2

Solution steps

5 x^{2} + 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 \cdot 4 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 5}, x_{2} = \frac{- 12 - 8}{2 \cdot 5}

x = \frac{- 12 + 8}{2 \cdot 5} : - \frac{2}{5}

x = \frac{- 12 - 8}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - 2

6 (2 x - 3) = 9 x - 18 + 3 x

(- 125) \frac{2}{3}

6 s^{2} = - 48

3 ∣ y + 4 ∣ > 12

40 \cdot 5

What are the solutions to the equation 5x^2+12x+4=0 ?
The solutions to the equation 5x^2+12x+4=0 are x=-2/5 ,x=-2
Find the zeros of 5x^2+12x+4=0
The zeros of 5x^2+12x+4=0 are x=-2/5 ,x=-2