What are the solutions to the equation m^2+m+2=0 ?

The solutions to the equation m^2+m+2=0 are m=-1/2+i(sqrt(7))/2 ,m=-1/2-i(sqrt(7))/2

Find the zeros of m^2+m+2=0

The zeros of m^2+m+2=0 are m=-1/2+i(sqrt(7))/2 ,m=-1/2-i(sqrt(7))/2

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m^{2} + m + 2 = 0

m = - \frac{1}{2} + i \frac{7}{2}, m = - \frac{1}{2} - i \frac{7}{2}

Solution steps

m^{2} + m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 2 : 7 i

m_{1, 2} = \frac{- 1 \pm 7 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 1 + 7 i}{2 \cdot 1}, m_{2} = \frac{- 1 - 7 i}{2 \cdot 1}

m = \frac{- 1 + 7 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{7}{2}

m = \frac{- 1 - 7 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

m = - \frac{1}{2} + i \frac{7}{2}, m = - \frac{1}{2} - i \frac{7}{2}

(2 x + 4) \cdot (x - 1) + (3 x + 5)^{2} = 3 (2 x + 5)^{2} + x

- x - 8 \geq - 5

- 12 x^{2} y - 3 x^{2} y

\frac{9}{20 m ^{4} + 100 m ^{3}} - \frac{2 m ^{2}}{3 m ^{2} + 16 m + 5}

- 8 < x - 7 < 8

What are the solutions to the equation m^2+m+2=0 ?
The solutions to the equation m^2+m+2=0 are m=-1/2+i(sqrt(7))/2 ,m=-1/2-i(sqrt(7))/2
Find the zeros of m^2+m+2=0
The zeros of m^2+m+2=0 are m=-1/2+i(sqrt(7))/2 ,m=-1/2-i(sqrt(7))/2