What are the solutions to the equation 12-t^2=0 ?

The solutions to the equation 12-t^2=0 are t=2sqrt(3),t=-2sqrt(3)

Find the zeros of 12-t^2=0

The zeros of 12-t^2=0 are t=2sqrt(3),t=-2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 - t^{2} = 0

t = 23, t = - 23

Solution steps

12 - t^{2} = 0

Move

12

to the right side

- t^{2} = - 12

Divide both sides by

- 1

t^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 12, t = - 12

12 = 23

- 12 = - 23

t = 23, t = - 23

\frac{3}{5} + \frac{6}{25}

x^{2} - 7 x + 28 = 0

6 (x - 5) = 5 x + 8

\frac{3}{4} - \frac{2}{7}

\frac{2}{7} = - \frac{8 x}{7} + \frac{6}{7}

What are the solutions to the equation 12-t^2=0 ?
The solutions to the equation 12-t^2=0 are t=2sqrt(3),t=-2sqrt(3)
Find the zeros of 12-t^2=0
The zeros of 12-t^2=0 are t=2sqrt(3),t=-2sqrt(3)