What is (\frac{16x^2-y^2)/(xy)}{4/y-1/x} ?

The solution to (\frac{16x^2-y^2)/(xy)}{4/y-1/x} is 4x+y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (\frac{16x^2-y^2)/(xy)}{4/y-1/x}

simplify

\frac{\frac{16 x ^{2} - y ^{2}}{x y}}{\frac{4}{y} - \frac{1}{x}}

4 x + y

Solution steps

\frac{\frac{16 x ^{2} - y ^{2}}{x y}}{\frac{4}{y} - \frac{1}{x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{16 x ^{2} - y ^{2}}{x y ( \frac{4}{y} - \frac{1}{x} )}

Cancel

\frac{16 x ^{2} - y ^{2}}{x y ( \frac{4}{y} - \frac{1}{x} )} : 4 x + y

= 4 x + y

i^{102}

- 2 m^{4} + 14 m^{2} - 6 m

3 y^{2} - 12 y + 12 = 0

2 2^{2}

28 n^{2} - 184 n - 96

What is (\frac{16x^2-y^2)/(xy)}{4/y-1/x} ?
The solution to (\frac{16x^2-y^2)/(xy)}{4/y-1/x} is 4x+y