What are the solutions to the equation x^2+10x+25=11 ?

The solutions to the equation x^2+10x+25=11 are x=-5+sqrt(11),x=-5-sqrt(11)

Find the zeros of x^2+10x+25=11

The zeros of x^2+10x+25=11 are x=-5+sqrt(11),x=-5-sqrt(11)

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x^{2} + 10 x + 25 = 11

x = - 5 + 11, x = - 5 - 11

Decimal Notation

x = - 1.68337 \dots, x = - 8.31662 \dots

Solution steps

x^{2} + 10 x + 25 = 11

Move

11

to the left side

x^{2} + 10 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 14 = 211

x_{1, 2} = \frac{- 10 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 11}{2 \cdot 1}

x = \frac{- 10 + 2 11}{2 \cdot 1} : - 5 + 11

x = \frac{- 10 - 2 11}{2 \cdot 1} : - 5 - 11

The solutions to the quadratic equation are:

x = - 5 + 11, x = - 5 - 11

8 (x - 1) - 2 x = - (x + 50)

3 + 7 x < 26

4 (x + 5) = - 2 (x - 28)

2 \cdot 9

3 x - 3 = 6 x + 4

What are the solutions to the equation x^2+10x+25=11 ?
The solutions to the equation x^2+10x+25=11 are x=-5+sqrt(11),x=-5-sqrt(11)
Find the zeros of x^2+10x+25=11
The zeros of x^2+10x+25=11 are x=-5+sqrt(11),x=-5-sqrt(11)