What are the solutions to the equation x^2-77=-2x+3 ?

The solutions to the equation x^2-77=-2x+3 are x=8,x=-10

Find the zeros of x^2-77=-2x+3

The zeros of x^2-77=-2x+3 are x=8,x=-10

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x^{2} - 77 = - 2 x + 3

x = 8, x = - 10

Solution steps

x^{2} - 77 = - 2 x + 3

Move

3

to the left side

x^{2} - 80 = - 2 x

Move

2 x

to the left side

x^{2} - 80 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 1}, x_{2} = \frac{- 2 - 18}{2 \cdot 1}

x = \frac{- 2 + 18}{2 \cdot 1} : 8

x = \frac{- 2 - 18}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

2 n + 3 \geq 4 (n + 4) - 3

7 x (a - b) - 3 y (a - b)

24 x^{2} - 1080 + 10800 = 0

∣ 5 x + 1 ∣ - 10 = - 5

- \frac{\frac{5}{3}}{- \frac{1}{8}}

What are the solutions to the equation x^2-77=-2x+3 ?
The solutions to the equation x^2-77=-2x+3 are x=8,x=-10
Find the zeros of x^2-77=-2x+3
The zeros of x^2-77=-2x+3 are x=8,x=-10