What are the solutions to the equation m^2-4m=140 ?

The solutions to the equation m^2-4m=140 are m=14,m=-10

Find the zeros of m^2-4m=140

The zeros of m^2-4m=140 are m=14,m=-10

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m^{2} - 4 m = 140

m = 14, m = - 10

Solution steps

m^{2} - 4 m = 140

Move

140

to the left side

m^{2} - 4 m - 140 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 140 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 140) = 24

m_{1, 2} = \frac{- ( - 4 ) \pm 24}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 24}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 24}{2 \cdot 1}

m = \frac{- ( - 4 ) + 24}{2 \cdot 1} : 14

m = \frac{- ( - 4 ) - 24}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

m = 14, m = - 10

x^{2} - 22 x + 40

- 4 = 6 x - 3 x^{2}

15 x - 2 = 10 x + 23

3 x - 5 < 19

x + x + \frac{1}{6} x = 13

What are the solutions to the equation m^2-4m=140 ?
The solutions to the equation m^2-4m=140 are m=14,m=-10
Find the zeros of m^2-4m=140
The zeros of m^2-4m=140 are m=14,m=-10