What are the solutions to the equation x^2+8=4 ?

The solutions to the equation x^2+8=4 are x=2i,x=-2i

Find the zeros of x^2+8=4

The zeros of x^2+8=4 are x=2i,x=-2i

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x^{2} + 8 = 4

x = 2 i, x = - 2 i

Solution steps

x^{2} + 8 = 4

Move

8

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

6 x - 4 \geq - 28

x^{2} - 5 x + 4 \geq 0

18 x^{2} + 4 x + 12 = 6 x^{2}

2 x + 0 = - 4

What are the solutions to the equation x^2+8=4 ?
The solutions to the equation x^2+8=4 are x=2i,x=-2i
Find the zeros of x^2+8=4
The zeros of x^2+8=4 are x=2i,x=-2i