What are the solutions to the equation 5x^2-2x=4 ?

The solutions to the equation 5x^2-2x=4 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5

Find the zeros of 5x^2-2x=4

The zeros of 5x^2-2x=4 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5

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5 x^{2} - 2 x = 4

x = \frac{1 + 21}{5}, x = \frac{1 - 21}{5}

Decimal Notation

x = 1.11651 \dots, x = - 0.71651 \dots

Solution steps

5 x^{2} - 2 x = 4

Move

4

to the left side

5 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 4) = 221

x_{1, 2} = \frac{- ( - 2 ) \pm 2 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 21}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2 21}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2 21}{2 \cdot 5} : \frac{1 + 21}{5}

x = \frac{- ( - 2 ) - 2 21}{2 \cdot 5} : \frac{1 - 21}{5}

The solutions to the quadratic equation are:

x = \frac{1 + 21}{5}, x = \frac{1 - 21}{5}

5 x + 4 - 6 x = 7 - x - 3

∣ 3 x - 1 ∣ = 6

3 (x + 6)^{2} = 75

m^{2} - 4 m + 4

60 = 3 x - \frac{5}{3} x

What are the solutions to the equation 5x^2-2x=4 ?
The solutions to the equation 5x^2-2x=4 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5
Find the zeros of 5x^2-2x=4
The zeros of 5x^2-2x=4 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5