What is (28p^9q^{-5})/(12p^{-6)q^7} ?

The solution to (28p^9q^{-5})/(12p^{-6)q^7} is (7p^{15})/(3q^{12)}

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simplify (28p^9q^{-5})/(12p^{-6)q^7}

simplify

\frac{28 p ^{9} q ^{- 5}}{12 p ^{- 6} q ^{7}}

\frac{7 p ^{15}}{3 q ^{12}}

Solution steps

\frac{28 p ^{9} q ^{- 5}}{12 p ^{- 6} q ^{7}}

Factor the number:

28 = 4 \cdot 7

= \frac{4 \cdot 7 p ^{9} q ^{- 5}}{12 p ^{- 6} q ^{7}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 7 p ^{9} q ^{- 5}}{4 \cdot 3 p ^{- 6} q ^{7}}

Cancel the common factor:

4

= \frac{7 p ^{9} q ^{- 5}}{3 p ^{- 6} q ^{7}}

Simplify

\frac{p ^{9}}{p ^{- 6}} : p^{15}

= \frac{7 p ^{15} q ^{- 5}}{3 q ^{7}}

Simplify

\frac{q ^{- 5}}{q ^{7}} : \frac{1}{q ^{12}}

= \frac{7 p ^{15}}{3 q ^{12}}

4 c^{2} + 13 c - 12

x^{2} - 4 x = 12

42 \cdot 22

(x - 1)^{2} - 4 < 0

\frac{( 79 + 7 i )}{( 6 - 7 i )}

What is (28p^9q^{-5})/(12p^{-6)q^7} ?
The solution to (28p^9q^{-5})/(12p^{-6)q^7} is (7p^{15})/(3q^{12)}