What are the solutions to the equation 5a^2=26a+24 ?

The solutions to the equation 5a^2=26a+24 are a=6,a=-4/5

Find the zeros of 5a^2=26a+24

The zeros of 5a^2=26a+24 are a=6,a=-4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 a^{2} = 26 a + 24

a = 6, a = - \frac{4}{5}

Decimal Notation

a = 6, a = - 0.8

Solution steps

5 a^{2} = 26 a + 24

Move

24

to the left side

5 a^{2} - 24 = 26 a

Move

26 a

to the left side

5 a^{2} - 24 - 26 a = 0

Write in the standard form

a x^{2} + b x + c = 0

5 a^{2} - 26 a - 24 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 (- 24) = 34

a_{1, 2} = \frac{- ( - 26 ) \pm 34}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 26 ) + 34}{2 \cdot 5}, a_{2} = \frac{- ( - 26 ) - 34}{2 \cdot 5}

a = \frac{- ( - 26 ) + 34}{2 \cdot 5} : 6

a = \frac{- ( - 26 ) - 34}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

a = 6, a = - \frac{4}{5}

3 x = 9 x^{2} - 10

10 v^{2} - 1 v + 9 = 0

2 x - 6 - 2 < 0

\frac{x}{4} = 16

(2 x - 2)^{2} + 1 = 6 - (x - 1)^{2}

What are the solutions to the equation 5a^2=26a+24 ?
The solutions to the equation 5a^2=26a+24 are a=6,a=-4/5
Find the zeros of 5a^2=26a+24
The zeros of 5a^2=26a+24 are a=6,a=-4/5