What are the solutions to the equation 0=-4x^2-10x-5 ?

The solutions to the equation 0=-4x^2-10x-5 are x=-(5+sqrt(5))/4 ,x=-(5-sqrt(5))/4

Find the zeros of 0=-4x^2-10x-5

The zeros of 0=-4x^2-10x-5 are x=-(5+sqrt(5))/4 ,x=-(5-sqrt(5))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 4 x^{2} - 10 x - 5

x = - \frac{5 + 5}{4}, x = - \frac{5 - 5}{4}

Decimal Notation

x = - 1.80901 \dots, x = - 0.69098 \dots

Solution steps

0 = - 4 x^{2} - 10 x - 5

Switch sides

- 4 x^{2} - 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 4 ) ( - 5 )}{2 ( - 4 )}

(- 10)^{2} - 4 (- 4) (- 5) = 25

x_{1, 2} = \frac{- ( - 10 ) \pm 2 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 5}{2 ( - 4 )}, x_{2} = \frac{- ( - 10 ) - 2 5}{2 ( - 4 )}

x = \frac{- ( - 10 ) + 2 5}{2 ( - 4 )} : - \frac{5 + 5}{4}

x = \frac{- ( - 10 ) - 2 5}{2 ( - 4 )} : - \frac{5 - 5}{4}

The solutions to the quadratic equation are:

x = - \frac{5 + 5}{4}, x = - \frac{5 - 5}{4}

3 a^{2} - 8 a + 5

\frac{1}{2} \cdot 9 \cdot 4

lo g_{e} (\frac{1}{e})

x^{3} - 9 x \geq 0

ln (\frac{x ^{2}}{y z ^{3}})

What are the solutions to the equation 0=-4x^2-10x-5 ?
The solutions to the equation 0=-4x^2-10x-5 are x=-(5+sqrt(5))/4 ,x=-(5-sqrt(5))/4
Find the zeros of 0=-4x^2-10x-5
The zeros of 0=-4x^2-10x-5 are x=-(5+sqrt(5))/4 ,x=-(5-sqrt(5))/4