What is factor j^2+20j+19 ?

The solution to factor j^2+20j+19 is (j+1)(j+19)

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factor j^2+20j+19

factor

j^{2} + 20 j + 19

(j + 1) (j + 19)

Solution steps

j^{2} + 20 j + 19

Break the expression into groups

= (j^{2} + j) + (19 j + 19)

Factor out

j

from

j^{2} + j : j (j + 1)

Factor out

19

from

19 j + 19 : 19 (j + 1)

= j (j + 1) + 19 (j + 1)

Factor out common term

j + 1

= (j + 1) (j + 19)

\frac{4}{5} v < \frac{7}{15}

\frac{7}{2} (3)

(4 x)^{- 4}

3 - x < x + 2 < - x + 5

- 7 < - 3