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Popular >

3|x-4|+5<= 17

Solution

3 ∣ x - 4 ∣ + 5 \leq 17

Solution

0 \leq x \leq 8

+1

Interval Notation

[0, 8]

Solution steps

3 ∣ x - 4 ∣ + 5 \leq 17

Move

5

to the right side

3 ∣ x - 4 ∣ \leq 12

Divide both sides by

3

∣ x - 4 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x - 4 \leq 4

x - 4 \geq - 4 and x - 4 \leq 4

x \geq 0 and x \leq 8

Merge Overlapping Intervals

0 \leq x \leq 8

Popular Examples

simplify (((1.17)(2.03)^2))/2+4.4793735 simplify

\frac{( ( 1.17 ) ( 2.03 ) ^{2} )}{2} + 4.4793735

simplify 6/11*7/3 simplify

\frac{6}{11} \cdot \frac{7}{3}

- 2 + 3 (3) \geq \frac{1}{4}

factor 3x^3+4x^2-30x-40 factor

3 x^{3} + 4 x^{2} - 30 x - 40

9.2(x+6.4)=132.48

9.2 (x + 6.4) = 132.48

Frequently Asked Questions (FAQ)

What is 3|x-4|+5<= 17 ?
The solution to 3|x-4|+5<= 17 is 0<= x<= 8