What are the solutions to the equation x^2+6=5x-65-x ?

The solutions to the equation x^2+6=5x-65-x are x=2+sqrt(67)i,x=2-sqrt(67)i

Find the zeros of x^2+6=5x-65-x

The zeros of x^2+6=5x-65-x are x=2+sqrt(67)i,x=2-sqrt(67)i

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x^{2} + 6 = 5 x - 65 - x

x = 2 + 67 i, x = 2 - 67 i

Solution steps

x^{2} + 6 = 5 x - 65 - x

Refine

x^{2} + 6 = 4 x - 65

Move

65

to the left side

x^{2} + 71 = 4 x

Move

4 x

to the left side

x^{2} + 71 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 71}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 71 : 267 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 67 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 67 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 67 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 67 i}{2 \cdot 1} : 2 + 67 i

x = \frac{- ( - 4 ) - 2 67 i}{2 \cdot 1} : 2 - 67 i

The solutions to the quadratic equation are:

x = 2 + 67 i, x = 2 - 67 i

x y^{3} 8 x^{3} y^{4}

m^{2} = 15 m - 56

115 = - 15 t^{2} + 120 t + 10

a^{2} - 4 a

(- \frac{1}{3})^{3}

What are the solutions to the equation x^2+6=5x-65-x ?
The solutions to the equation x^2+6=5x-65-x are x=2+sqrt(67)i,x=2-sqrt(67)i
Find the zeros of x^2+6=5x-65-x
The zeros of x^2+6=5x-65-x are x=2+sqrt(67)i,x=2-sqrt(67)i