What are the solutions to the equation x^2=512 ?

The solutions to the equation x^2=512 are x=16sqrt(2),x=-16sqrt(2)

Find the zeros of x^2=512

The zeros of x^2=512 are x=16sqrt(2),x=-16sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 512

x = 162, x = - 162

Decimal Notation

x = 22.62741 \dots, x = - 22.62741 \dots

Solution steps

x^{2} = 512

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 512, x = - 512

512 = 162

- 512 = - 162

x = 162, x = - 162

\frac{8.95 \cdot 1 0 ^{5}}{1860}

x^{2} + 3 x + 5 > 0

299

2 X + 3 X - 5 + 8 + X = 2 (2 X + 5) + 15

\frac{3 x ^{10} y ^{8} z ^{2}}{x ^{5} y ^{6} z ^{11}}

What are the solutions to the equation x^2=512 ?
The solutions to the equation x^2=512 are x=16sqrt(2),x=-16sqrt(2)
Find the zeros of x^2=512
The zeros of x^2=512 are x=16sqrt(2),x=-16sqrt(2)