en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3|z+4|-13<=-1

Solution

3 ∣ z + 4 ∣ - 13 \leq - 1

Solution

- 8 \leq z \leq 0

+1

Interval Notation

[- 8, 0]

Solution steps

3 ∣ z + 4 ∣ - 13 \leq - 1

Move

13

to the right side

3 ∣ z + 4 ∣ \leq 12

Divide both sides by

3

∣ z + 4 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq z + 4 \leq 4

z + 4 \geq - 4 and z + 4 \leq 4

z \geq - 8 and z \leq 0

Merge Overlapping Intervals

- 8 \leq z \leq 0

Popular Examples

-1/9 (x-27)+1/3 (x+3)=x+25

- \frac{1}{9} (x - 27) + \frac{1}{3} (x + 3) = x + 25

50 d^{2} - 26 = 0

6 x (x - 1) = 56 - 11 x

3 x \leq - \frac{5}{4}

x (x - 2) - 6 > - 6

Frequently Asked Questions (FAQ)

What is 3|z+4|-13<=-1 ?
The solution to 3|z+4|-13<=-1 is -8<= z<= 0