What are the solutions to the equation x^2= 1/8 ?

The solutions to the equation x^2= 1/8 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))

Find the zeros of x^2= 1/8

The zeros of x^2= 1/8 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))

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x^{2} = \frac{1}{8}

x = \frac{1}{2 2}, x = - \frac{1}{2 2}

Solution steps

x^{2} = \frac{1}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{8}, x = - \frac{1}{8}

\frac{1}{8} = \frac{1}{2 2}

- \frac{1}{8} = - \frac{1}{2 2}

x = \frac{1}{2 2}, x = - \frac{1}{2 2}

t^{2} - \frac{64}{121} = 0

2^{k} \geq 36

n^{2} + 16 n + 63

- 140 < 10 x

x^{2} = 16 x

What are the solutions to the equation x^2= 1/8 ?
The solutions to the equation x^2= 1/8 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))
Find the zeros of x^2= 1/8
The zeros of x^2= 1/8 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))