What are the solutions to the equation 2x^2-4x+5=6 ?

The solutions to the equation 2x^2-4x+5=6 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

Find the zeros of 2x^2-4x+5=6

The zeros of 2x^2-4x+5=6 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

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2 x^{2} - 4 x + 5 = 6

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

2 x^{2} - 4 x + 5 = 6

Move

6

to the left side

2 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 1) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 2} : \frac{2 + 6}{2}

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 2} : \frac{2 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

\frac{7}{45} \cdot \frac{9}{10}

4 x^{2} + 24 x + 36

10 t - 1.86 t^{2} = 0

\frac{4}{a + 3} + \frac{5}{a - 5}

\frac{3}{2} x - 10 = 50

What are the solutions to the equation 2x^2-4x+5=6 ?
The solutions to the equation 2x^2-4x+5=6 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2
Find the zeros of 2x^2-4x+5=6
The zeros of 2x^2-4x+5=6 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2