What are the solutions to the equation log_{5}(6)+log_{5}(2)x^2=log_{5}(48) ?

The solutions to the equation log_{5}(6)+log_{5}(2)x^2=log_{5}(48) are x=sqrt(3),x=-sqrt(3)

Find the zeros of log_{5}(6)+log_{5}(2)x^2=log_{5}(48)

The zeros of log_{5}(6)+log_{5}(2)x^2=log_{5}(48) are x=sqrt(3),x=-sqrt(3)

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lo g_{5} (6) + lo g_{5} (2) x^{2} = lo g_{5} (48)

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

lo g_{5} (6) + lo g_{5} (2) x^{2} = lo g_{5} (48)

Move

lo g_{5} (6)

to the right side

lo g_{5} (2) x^{2} = 3 lo g_{5} (2)

Divide both sides by

lo g_{5} (2)

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

64 a^{2} b - 16 a^{3} + 18 a^{2} b - 9

(\frac{7}{25})^{2} + (\frac{24}{25})^{2}

\frac{3 x ^{3} y ^{- 1} z ^{- 1}}{x ^{- 4} y ^{0} z ^{0}}

\frac{1}{3} + \frac{3}{4}

7 - (- 3)

What are the solutions to the equation log_{5}(6)+log_{5}(2)x^2=log_{5}(48) ?
The solutions to the equation log_{5}(6)+log_{5}(2)x^2=log_{5}(48) are x=sqrt(3),x=-sqrt(3)
Find the zeros of log_{5}(6)+log_{5}(2)x^2=log_{5}(48)
The zeros of log_{5}(6)+log_{5}(2)x^2=log_{5}(48) are x=sqrt(3),x=-sqrt(3)