What are the solutions to the equation 5x^2+9x=-18+4x^2 ?

The solutions to the equation 5x^2+9x=-18+4x^2 are x=-3,x=-6

Find the zeros of 5x^2+9x=-18+4x^2

The zeros of 5x^2+9x=-18+4x^2 are x=-3,x=-6

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5 x^{2} + 9 x = - 18 + 4 x^{2}

x = - 3, x = - 6

Solution steps

5 x^{2} + 9 x = - 18 + 4 x^{2}

Move

4 x^{2}

to the left side

x^{2} + 9 x = - 18

Move

18

to the left side

x^{2} + 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 \cdot 1}, x_{2} = \frac{- 9 - 3}{2 \cdot 1}

x = \frac{- 9 + 3}{2 \cdot 1} : - 3

x = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 3, x = - 6

1 \cdot 1 0^{- 9}

(- 2 h + 9) (9 h - 2) = (- 2 h + 9) (9 h - 2)

8 + 5 y \leq 21 + 6 y

∣ x - 8 ∣ = - 9

(\frac{2 - \frac{1}{2}}{\frac{1}{2}})^{- 1}

What are the solutions to the equation 5x^2+9x=-18+4x^2 ?
The solutions to the equation 5x^2+9x=-18+4x^2 are x=-3,x=-6
Find the zeros of 5x^2+9x=-18+4x^2
The zeros of 5x^2+9x=-18+4x^2 are x=-3,x=-6