What are the solutions to the equation 1/4 h^2-3/4 h=0 ?

The solutions to the equation 1/4 h^2-3/4 h=0 are h=3,h=0

Find the zeros of 1/4 h^2-3/4 h=0

The zeros of 1/4 h^2-3/4 h=0 are h=3,h=0

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\frac{1}{4} h^{2} - \frac{3}{4} h = 0

h = 3, h = 0

Solution steps

\frac{1}{4} h^{2} - \frac{3}{4} h = 0

Multiply both sides by

4

h^{2} - 3 h = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

h_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, h_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

h = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

h = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

h = 3, h = 0

(\frac{r}{s})^{4}

12 x^{2} - 4 x = 20 + 10 x

(- x - 4) \cdot 2 = 3 \cdot (- 3 x + 1) + 12

2^{n} \cdot 3^{n}

\frac{1}{1 + e ^{- 3}}

What are the solutions to the equation 1/4 h^2-3/4 h=0 ?
The solutions to the equation 1/4 h^2-3/4 h=0 are h=3,h=0
Find the zeros of 1/4 h^2-3/4 h=0
The zeros of 1/4 h^2-3/4 h=0 are h=3,h=0