What are the solutions to the equation 0=8x^2+6x+4 ?

The solutions to the equation 0=8x^2+6x+4 are x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8

Find the zeros of 0=8x^2+6x+4

The zeros of 0=8x^2+6x+4 are x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8

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0 = 8 x^{2} + 6 x + 4

x = - \frac{3}{8} + i \frac{23}{8}, x = - \frac{3}{8} - i \frac{23}{8}

Solution steps

0 = 8 x^{2} + 6 x + 4

Switch sides

8 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

Simplify

6^{2} - 4 \cdot 8 \cdot 4 : 223 i

x_{1, 2} = \frac{- 6 \pm 2 23 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 2 23 i}{2 \cdot 8}, x_{2} = \frac{- 6 - 2 23 i}{2 \cdot 8}

x = \frac{- 6 + 2 23 i}{2 \cdot 8} : - \frac{3}{8} + i \frac{23}{8}

x = \frac{- 6 - 2 23 i}{2 \cdot 8} : - \frac{3}{8} - i \frac{23}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{23}{8}, x = - \frac{3}{8} - i \frac{23}{8}

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What are the solutions to the equation 0=8x^2+6x+4 ?
The solutions to the equation 0=8x^2+6x+4 are x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8
Find the zeros of 0=8x^2+6x+4
The zeros of 0=8x^2+6x+4 are x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8