What are the solutions to the equation 0=-2x^2+20 ?

The solutions to the equation 0=-2x^2+20 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 0=-2x^2+20

The zeros of 0=-2x^2+20 are x=sqrt(10),x=-sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 2 x^{2} + 20

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

0 = - 2 x^{2} + 20

Switch sides

- 2 x^{2} + 20 = 0

Move

20

to the right side

- 2 x^{2} = - 20

Divide both sides by

- 2

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

38.6 \cdot \frac{1}{15.999 ( 2 )}

4 x^{2} - 5 x + 4 = 0

3 x^{2} + 4 x + 2 = 0

\frac{112}{8}

∣ 7 + 8 m ∣ - 5 \geq - 11

What are the solutions to the equation 0=-2x^2+20 ?
The solutions to the equation 0=-2x^2+20 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 0=-2x^2+20
The zeros of 0=-2x^2+20 are x=sqrt(10),x=-sqrt(10)