What are the solutions to the equation x^2+18x+81=0 ?

The solutions to the equation x^2+18x+81=0 are x=-9

Find the zeros of x^2+18x+81=0

The zeros of x^2+18x+81=0 are x=-9

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x^{2} + 18 x + 81 = 0

x = - 9

Solution steps

x^{2} + 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

x = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

x = - 9

The solution to the quadratic equation is:

x = - 9

- \frac{8}{16}

\frac{1}{3} - 2 m < \frac{5 + m}{2}

154

x^{4} - 4 x^{3} + 16 x - 16

\frac{n - 3}{4} + \frac{n + 5}{7} = \frac{5}{14}

What are the solutions to the equation x^2+18x+81=0 ?
The solutions to the equation x^2+18x+81=0 are x=-9
Find the zeros of x^2+18x+81=0
The zeros of x^2+18x+81=0 are x=-9