What is the answer to x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x) ?

The answer to x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x) is x=0

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x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x)

x^{2} - 5 x + 15 = x (x - 3) - 14 + 5 (x - 2) + 3 (13 - 2 x)

x = 0

Solution steps

x^{2} - 5 x + 15 = x (x - 3) - 14 + 5 (x - 2) + 3 (13 - 2 x)

Expand

x (x - 3) - 14 + 5 (x - 2) + 3 (13 - 2 x) : x^{2} - 4 x + 15

x^{2} - 5 x + 15 = x^{2} - 4 x + 15

Move

15

to the right side

x^{2} - 5 x = x^{2} - 4 x

Subtract

x^{2} - 4 x

from both sides

x^{2} - 5 x - (x^{2} - 4 x) = x^{2} - 4 x - (x^{2} - 4 x)

Simplify

- x = 0

Divide both sides by

- 1

x = 0

x^{2} = 6 x + 91

\frac{1}{2} 12 - \frac{1}{3} 18 + \frac{3}{4} 48 + \frac{1}{6} 72

2 a^{2} - 8 a

- x^{2} - 7 x - 12 \leq - 2

6^{n} + 2^{n}

What is the answer to x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x) ?
The answer to x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x) is x=0
Solve for x: x^2-5x+15=x(x-3)-14+5(x-2)+3(13-2x)
The solution is x=0