What are the solutions to the equation 0=10+3y-y^2 ?

The solutions to the equation 0=10+3y-y^2 are y=-2,y=5

Find the zeros of 0=10+3y-y^2

The zeros of 0=10+3y-y^2 are y=-2,y=5

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0 = 10 + 3 y - y^{2}

y = - 2, y = 5

Solution steps

0 = 10 + 3 y - y^{2}

Switch sides

10 + 3 y - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- y^{2} + 3 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 10 = 7

y_{1, 2} = \frac{- 3 \pm 7}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 3 + 7}{2 ( - 1 )}, y_{2} = \frac{- 3 - 7}{2 ( - 1 )}

y = \frac{- 3 + 7}{2 ( - 1 )} : - 2

y = \frac{- 3 - 7}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

y = - 2, y = 5

55 y^{2} + 51 y - 18

- x - 35 = 11 - 3 x

\frac{5}{6} \cdot \frac{4}{15}

h (- 30) = - 16 (- 30)^{2} + 960 (- 30)

2 d^{2} - d - 0.36 = 0

What are the solutions to the equation 0=10+3y-y^2 ?
The solutions to the equation 0=10+3y-y^2 are y=-2,y=5
Find the zeros of 0=10+3y-y^2
The zeros of 0=10+3y-y^2 are y=-2,y=5