What are the solutions to the equation 2x^2-4x+6=0 ?

The solutions to the equation 2x^2-4x+6=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 2x^2-4x+6=0

The zeros of 2x^2-4x+6=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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2 x^{2} - 4 x + 6 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

2 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 6 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2} : 1 + 2 i

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

- 2 ∣ 4 - x ∣ + \frac{5}{2} = 1

- 2 < 3 x + 1

x^{2} + 8 x y + 12 y^{2}

\frac{2 - 6 i}{3 i}

4 x^{3} - 2 x^{2}

What are the solutions to the equation 2x^2-4x+6=0 ?
The solutions to the equation 2x^2-4x+6=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 2x^2-4x+6=0
The zeros of 2x^2-4x+6=0 are x=1+sqrt(2)i,x=1-sqrt(2)i