What is 4x+4<= 9x+84x+4<= 9x+8 ?

The solution to 4x+4<= 9x+84x+4<= 9x+8 is 0<= x<= 1/21

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4x+4<= 9x+84x+4<= 9x+8

4 x + 4 \leq 9 x + 84 x + 4 \leq 9 x + 8

0 \leq x \leq \frac{1}{21}

Interval Notation

[0, \frac{1}{21}]

Decimal Notation

0 \leq x \leq 0.04761 \dots

Solution steps

4 x + 4 \leq 9 x + 84 x + 4 \leq 9 x + 8

a \leq u \leq b

then

a \leq u and u \leq b

4 x + 4 \leq 9 x + 84 x + 4 and 9 x + 84 x + 4 \leq 9 x + 8

4 x + 4 \leq 9 x + 84 x + 4 : x \geq 0

9 x + 84 x + 4 \leq 9 x + 8 : x \leq \frac{1}{21}

Combine the intervals

x \geq 0 and x \leq \frac{1}{21}

Merge Overlapping Intervals

0 \leq x \leq \frac{1}{21}

\frac{4 ( x + 5 )}{5} = 12

- \frac{12}{3}

\frac{a}{7} - 3 = - 2

2 x + 2 \leq 10

x^{3} - 1000

What is 4x+4<= 9x+84x+4<= 9x+8 ?
The solution to 4x+4<= 9x+84x+4<= 9x+8 is 0<= x<= 1/21