What is ((r^3s^{-1})/(r^2s^6))^{-1} ?

The solution to ((r^3s^{-1})/(r^2s^6))^{-1} is (s^7)/r

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((r^3s^{-1})/(r^2s^6))^{-1}

simplify

(\frac{r ^{3} s ^{- 1}}{r ^{2} s ^{6}})^{- 1}

\frac{s ^{7}}{r}

Solution steps

(\frac{r ^{3} s ^{- 1}}{r ^{2} s ^{6}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{r ^{3} s ^{- 1}}{r ^{2} s ^{6}})^{- 1} = \frac{1}{\frac{r ^{3} s ^{- 1}}{r ^{2} s ^{6}}}

= \frac{1}{\frac{r ^{3} s ^{- 1}}{r ^{2} s ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{r ^{2} s ^{6}}{r ^{3} s ^{- 1}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{r ^{2}}{r ^{3}} = \frac{1}{r ^{3 - 2}}

= \frac{s ^{6}}{s ^{- 1} r ^{3 - 2}}

Subtract the numbers:

3 - 2 = 1

= \frac{s ^{6}}{r s ^{- 1}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{s ^{6}}{s ^{- 1}} = s^{6 - (- 1)}

= \frac{s ^{6 - (- 1)}}{r}

Subtract the numbers:

6 - (- 1) = 7

= \frac{s ^{7}}{r}

2 x + 3 \leq 5

∣ 3 - x ∣ > - 2

\frac{x + 5}{9} = - 1

\frac{1.5 \cdot 1 0 ^{- 7}}{1.8 \cdot 1 0 ^{- 8}}

- 4 r > 16

What is ((r^3s^{-1})/(r^2s^6))^{-1} ?
The solution to ((r^3s^{-1})/(r^2s^6))^{-1} is (s^7)/r