What are the solutions to the equation x^2+6^2=12^2 ?

The solutions to the equation x^2+6^2=12^2 are x=6sqrt(3),x=-6sqrt(3)

Find the zeros of x^2+6^2=12^2

The zeros of x^2+6^2=12^2 are x=6sqrt(3),x=-6sqrt(3)

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x^{2} + 6^{2} = 1 2^{2}

x = 63, x = - 63

Decimal Notation

x = 10.39230 \dots, x = - 10.39230 \dots

Solution steps

x^{2} + 6^{2} = 1 2^{2}

Move

6^{2}

to the right side

x^{2} = 108

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 108, x = - 108

108 = 63

- 108 = - 63

x = 63, x = - 63

- 3 < 5 - \frac{2}{x} < 1

3 x - 3 = 2 x + 4

- 9 \leq 5 + 2 x < - 5

- 2 < \frac{6 - 2 x}{4} \leq 5

- 6 (w - 4) + 8 w = 2 (w + 9)

What are the solutions to the equation x^2+6^2=12^2 ?
The solutions to the equation x^2+6^2=12^2 are x=6sqrt(3),x=-6sqrt(3)
Find the zeros of x^2+6^2=12^2
The zeros of x^2+6^2=12^2 are x=6sqrt(3),x=-6sqrt(3)