What are the solutions to the equation 3d^2+13d-16=0 ?

The solutions to the equation 3d^2+13d-16=0 are d=1,d=-16/3

Find the zeros of 3d^2+13d-16=0

The zeros of 3d^2+13d-16=0 are d=1,d=-16/3

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3 d^{2} + 13 d - 16 = 0

d = 1, d = - \frac{16}{3}

Decimal Notation

d = 1, d = - 5.33333 \dots

Solution steps

3 d^{2} + 13 d - 16 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 (- 16) = 19

d_{1, 2} = \frac{- 13 \pm 19}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- 13 + 19}{2 \cdot 3}, d_{2} = \frac{- 13 - 19}{2 \cdot 3}

d = \frac{- 13 + 19}{2 \cdot 3} : 1

d = \frac{- 13 - 19}{2 \cdot 3} : - \frac{16}{3}

The solutions to the quadratic equation are:

d = 1, d = - \frac{16}{3}

\frac{x}{3} - \frac{3 x}{4} = 2

3 x + 7 = x + 13

5 (4)^{\frac{1}{4}} + 15 (4)^{\frac{1}{2}} + 9

\frac{3}{8} - \frac{11}{6}

5 x^{2} + 500 = 844.45

What are the solutions to the equation 3d^2+13d-16=0 ?
The solutions to the equation 3d^2+13d-16=0 are d=1,d=-16/3
Find the zeros of 3d^2+13d-16=0
The zeros of 3d^2+13d-16=0 are d=1,d=-16/3