What are the solutions to the equation 2z^2=4z ?

The solutions to the equation 2z^2=4z are z=0,z=2

Find the zeros of 2z^2=4z

The zeros of 2z^2=4z are z=0,z=2

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2 z^{2} = 4 z

z = 0, z = 2

Solution steps

2 z^{2} = 4 z

Move

4 z

to the left side

2 z^{2} - 4 z = 0

Factor

2 z^{2} - 4 z : 2 z (z - 2)

2 z (z - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

z = 0 or z - 2 = 0

Solve

z - 2 = 0 : z = 2

The solutions to the quadratic equation are:

z = 0, z = 2

n^{2} + n - 6

40.5

3 x^{2} - 7 x y - 6 y^{2}

2 p^{2} - 3 p - 7 = 0

(\frac{1}{9})^{3 t + 5} \geq (\frac{1}{243})^{t - 6}

What are the solutions to the equation 2z^2=4z ?
The solutions to the equation 2z^2=4z are z=0,z=2
Find the zeros of 2z^2=4z
The zeros of 2z^2=4z are z=0,z=2