What are the solutions to the equation 3y^2-7y+2=0 ?

The solutions to the equation 3y^2-7y+2=0 are y=2,y= 1/3

Find the zeros of 3y^2-7y+2=0

The zeros of 3y^2-7y+2=0 are y=2,y= 1/3

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3 y^{2} - 7 y + 2 = 0

y = 2, y = \frac{1}{3}

Decimal Notation

y = 2, y = 0.33333 \dots

Solution steps

3 y^{2} - 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

y_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, y_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

y = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

y = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

y = 2, y = \frac{1}{3}

\frac{1}{4} - 3

45 \cdot 415

lo g_{\frac{1}{2}} (2)

4 x - 2 = 22

(\frac{1}{16})^{2}

What are the solutions to the equation 3y^2-7y+2=0 ?
The solutions to the equation 3y^2-7y+2=0 are y=2,y= 1/3
Find the zeros of 3y^2-7y+2=0
The zeros of 3y^2-7y+2=0 are y=2,y= 1/3