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Popular >

5|x+10|+2<= 17

Solution

5 ∣ x + 10 ∣ + 2 \leq 17

Solution

- 13 \leq x \leq - 7

+1

Interval Notation

[- 13, - 7]

Solution steps

5 ∣ x + 10 ∣ + 2 \leq 17

Move

2

to the right side

5 ∣ x + 10 ∣ \leq 15

Divide both sides by

5

∣ x + 10 ∣ \leq 3

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 3 \leq x + 10 \leq 3

x + 10 \geq - 3 and x + 10 \leq 3

x \geq - 13 and x \leq - 7

Merge Overlapping Intervals

- 13 \leq x \leq - 7

Popular Examples

∣ a ∣ > 5

simplify (-1/(sqrt(x^2-1)))^2 simplify

(- \frac{1}{x ^{2} - 1})^{2}

simplify b^{-3/5}simplify

b^{- \frac{3}{5}}

5 x - 4 = 16

simplify 4/(2/3)simplify

\frac{4}{\frac{2}{3}}

Frequently Asked Questions (FAQ)

What is 5|x+10|+2<= 17 ?
The solution to 5|x+10|+2<= 17 is -13<= x<=-7