What is ((-4x^2)/(2x^{-1)})^{-1} ?

The solution to ((-4x^2)/(2x^{-1)})^{-1} is -1/(2x^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((-4x^2)/(2x^{-1)})^{-1}

simplify

(\frac{- 4 x ^{2}}{2 x ^{- 1}})^{- 1}

- \frac{1}{2 x ^{3}}

Solution steps

(\frac{- 4 x ^{2}}{2 x ^{- 1}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{- 4 x ^{2}}{2 x ^{- 1}})^{- 1} = \frac{1}{\frac{- 4 x ^{2}}{2 x ^{- 1}}}

= \frac{1}{\frac{- 4 x ^{2}}{2 x ^{- 1}}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= \frac{1}{- \frac{4 x ^{2}}{2 x ^{- 1}}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{\frac{4 x ^{2}}{2 x ^{- 1}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

\frac{1}{\frac{4 x ^{2}}{2 x ^{- 1}}} = \frac{2 x ^{- 1}}{4 x ^{2}}

= - \frac{2 x ^{- 1}}{4 x ^{2}}

Cancel the common factor:

2

= \frac{x ^{- 1}}{2 x ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{- 1}}{x ^{2}} = \frac{1}{x ^{2 - (- 1)}}

= \frac{1}{2 x ^{2 - (- 1)}}

Subtract the numbers:

2 - (- 1) = 3

= - \frac{1}{2 x ^{3}}

4 x^{2} - 25 b^{2}

55 (4 - 87)

\frac{3}{8} x - 17.5 = - 23.5

100 a^{3} + 120 a^{2} - 60 a - 72

(x + 6)^{2} - (x + 6) - 6 = 0

What is ((-4x^2)/(2x^{-1)})^{-1} ?
The solution to ((-4x^2)/(2x^{-1)})^{-1} is -1/(2x^3)