What are the solutions to the equation -248u^2-15400u+1012800=13200(40+u) ?

The solutions to the equation -248u^2-15400u+1012800=13200(40+u) are u=15,u=-4040/31

Find the zeros of -248u^2-15400u+1012800=13200(40+u)

The zeros of -248u^2-15400u+1012800=13200(40+u) are u=15,u=-4040/31

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- 248 u^{2} - 15400 u + 1012800 = 13200 (40 + u)

u = 15, u = - \frac{4040}{31}

Decimal Notation

u = 15, u = - 130.32258 \dots

Solution steps

- 248 u^{2} - 15400 u + 1012800 = 13200 (40 + u)

Expand

13200 (40 + u) : 528000 + 13200 u

- 248 u^{2} - 15400 u + 1012800 = 528000 + 13200 u

Move

13200 u

to the left side

- 248 u^{2} - 28600 u + 1012800 = 528000

Move

528000

to the left side

- 248 u^{2} - 28600 u + 484800 = 0

Factor

- 248 u^{2} - 28600 u + 484800 : - 8 (u - 15) (31 u + 4040)

- 8 (u - 15) (31 u + 4040) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u - 15 = 0 or 31 u + 4040 = 0

Solve

u - 15 = 0 : u = 15

Solve

31 u + 4040 = 0 : u = - \frac{4040}{31}

The solutions to the quadratic equation are:

u = 15, u = - \frac{4040}{31}

0.8097840332 = \frac{y}{57}

- \frac{16}{9} = - \frac{4}{3} (\frac{5}{3} + n)

- 9 a^{4} + 6 a^{3} - 3 a^{2}

216 b^{2} - 150

5 x^{2} + 9 x + 4

What are the solutions to the equation -248u^2-15400u+1012800=13200(40+u) ?
The solutions to the equation -248u^2-15400u+1012800=13200(40+u) are u=15,u=-4040/31
Find the zeros of -248u^2-15400u+1012800=13200(40+u)
The zeros of -248u^2-15400u+1012800=13200(40+u) are u=15,u=-4040/31