What are the solutions to the equation 2x^2=8x-3 ?

The solutions to the equation 2x^2=8x-3 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2

Find the zeros of 2x^2=8x-3

The zeros of 2x^2=8x-3 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2

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2 x^{2} = 8 x - 3

x = \frac{4 + 10}{2}, x = \frac{4 - 10}{2}

Solution steps

2 x^{2} = 8 x - 3

Move

3

to the left side

2 x^{2} + 3 = 8 x

Move

8 x

to the left side

2 x^{2} + 3 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 3 = 210

x_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 10}{2 \cdot 2} : \frac{4 + 10}{2}

x = \frac{- ( - 8 ) - 2 10}{2 \cdot 2} : \frac{4 - 10}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 10}{2}, x = \frac{4 - 10}{2}

9 - 2

\frac{5 π}{3} + 2 π

(\frac{4}{3})^{\frac{3}{2}}

4 k^{2} - 31 k - 8

2 + 7 x = 4 + 2 x

What are the solutions to the equation 2x^2=8x-3 ?
The solutions to the equation 2x^2=8x-3 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2
Find the zeros of 2x^2=8x-3
The zeros of 2x^2=8x-3 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2