What are the solutions to the equation 4k^2-k+15=8 ?

The solutions to the equation 4k^2-k+15=8 are k= 1/8+i(sqrt(111))/8 ,k= 1/8-i(sqrt(111))/8

Find the zeros of 4k^2-k+15=8

The zeros of 4k^2-k+15=8 are k= 1/8+i(sqrt(111))/8 ,k= 1/8-i(sqrt(111))/8

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4 k^{2} - k + 15 = 8

k = \frac{1}{8} + i \frac{111}{8}, k = \frac{1}{8} - i \frac{111}{8}

Solution steps

4 k^{2} - k + 15 = 8

Move

8

to the left side

4 k^{2} - k + 7 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 7 : 111 i

k_{1, 2} = \frac{- ( - 1 ) \pm 111 i}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- ( - 1 ) + 111 i}{2 \cdot 4}, k_{2} = \frac{- ( - 1 ) - 111 i}{2 \cdot 4}

k = \frac{- ( - 1 ) + 111 i}{2 \cdot 4} : \frac{1}{8} + i \frac{111}{8}

k = \frac{- ( - 1 ) - 111 i}{2 \cdot 4} : \frac{1}{8} - i \frac{111}{8}

The solutions to the quadratic equation are:

k = \frac{1}{8} + i \frac{111}{8}, k = \frac{1}{8} - i \frac{111}{8}

- 14 x - 161 = - 371

4 x + x z - 40 y - 10 yz

4 x^{2} + 2 x - 8 = 0

\frac{48}{- 16}

3 a^{2} b + 6 ab - 5 a^{3} b^{2} + 8 a^{2} b x + 4 a b^{2} m

What are the solutions to the equation 4k^2-k+15=8 ?
The solutions to the equation 4k^2-k+15=8 are k= 1/8+i(sqrt(111))/8 ,k= 1/8-i(sqrt(111))/8
Find the zeros of 4k^2-k+15=8
The zeros of 4k^2-k+15=8 are k= 1/8+i(sqrt(111))/8 ,k= 1/8-i(sqrt(111))/8