What is factor j^2+2j-3 ?

The solution to factor j^2+2j-3 is (j-1)(j+3)

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factor j^2+2j-3

factor

j^{2} + 2 j - 3

(j - 1) (j + 3)

Solution steps

j^{2} + 2 j - 3

Break the expression into groups

= (j^{2} - j) + (3 j - 3)

Factor out

j

from

j^{2} - j : j (j - 1)

Factor out

3

from

3 j - 3 : 3 (j - 1)

= j (j - 1) + 3 (j - 1)

Factor out common term

j - 1

= (j - 1) (j + 3)

x^{2} + 7 x + 8 = 0

2 x - 3 = - 1

5 x^{2} + 8 x - 69 = 0

- 9 + 2 x < 1

\frac{9}{10} + \frac{4}{5} \cdot \frac{8}{15} - \frac{1}{5}