What are the solutions to the equation 6m+3=2m^2 ?

The solutions to the equation 6m+3=2m^2 are m=(3+sqrt(15))/2 ,m=(3-sqrt(15))/2

Find the zeros of 6m+3=2m^2

The zeros of 6m+3=2m^2 are m=(3+sqrt(15))/2 ,m=(3-sqrt(15))/2

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6 m + 3 = 2 m^{2}

m = \frac{3 + 15}{2}, m = \frac{3 - 15}{2}

Decimal Notation

m = 3.43649 \dots, m = - 0.43649 \dots

Solution steps

6 m + 3 = 2 m^{2}

Switch sides

2 m^{2} = 6 m + 3

Move

3

to the left side

2 m^{2} - 3 = 6 m

Move

6 m

to the left side

2 m^{2} - 3 - 6 m = 0

Write in the standard form

a x^{2} + b x + c = 0

2 m^{2} - 6 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 3) = 215

m_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 2 15}{2 \cdot 2}, m_{2} = \frac{- ( - 6 ) - 2 15}{2 \cdot 2}

m = \frac{- ( - 6 ) + 2 15}{2 \cdot 2} : \frac{3 + 15}{2}

m = \frac{- ( - 6 ) - 2 15}{2 \cdot 2} : \frac{3 - 15}{2}

The solutions to the quadratic equation are:

m = \frac{3 + 15}{2}, m = \frac{3 - 15}{2}

2 x \geq 6

\frac{7 y + 6}{6} > - 20

\frac{8 a ^{3} - 27}{9 - 12 a + 4 a ^{2}}

4 0^{2}

What are the solutions to the equation 6m+3=2m^2 ?
The solutions to the equation 6m+3=2m^2 are m=(3+sqrt(15))/2 ,m=(3-sqrt(15))/2
Find the zeros of 6m+3=2m^2
The zeros of 6m+3=2m^2 are m=(3+sqrt(15))/2 ,m=(3-sqrt(15))/2