What is \sqrt[3]{-16}*\sqrt[3]{4} ?

The solution to \sqrt[3]{-16}*\sqrt[3]{4} is -4

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simplify \sqrt[3]{-16}*\sqrt[3]{4}

simplify

- 4

Solution steps

Apply radical rule:

n

is odd

Apply radical rule:

Multiply the numbers:

2 \cdot 4 = 8

Factor the number:

8 = 2^{3}

Apply radical rule:

= - 2 \cdot 2

Multiply the numbers:

- 2 \cdot 2 = - 4

= - 4

2 ∣ x - 5 ∣ < 32

lo g_{64} (16)

- 3 i \cdot 6 i - 3 (- 7 + 6 i)

(x^{6})^{2}

- \frac{n}{7} \geq 3

What is \sqrt[3]{-16}*\sqrt[3]{4} ?
The solution to \sqrt[3]{-16}*\sqrt[3]{4} is -4