What are the solutions to the equation 10^2+11^2=x^2 ?

The solutions to the equation 10^2+11^2=x^2 are x=sqrt(221),x=-sqrt(221)

Find the zeros of 10^2+11^2=x^2

The zeros of 10^2+11^2=x^2 are x=sqrt(221),x=-sqrt(221)

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1 0^{2} + 1 1^{2} = x^{2}

x = 221, x = - 221

Decimal Notation

x = 14.86606 \dots, x = - 14.86606 \dots

Solution steps

1 0^{2} + 1 1^{2} = x^{2}

Switch sides

x^{2} = 1 0^{2} + 1 1^{2}

Simplify

1 0^{2} + 1 1^{2} : 221

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 221, x = - 221

54 = 36 - 9 b

82

x^{2} - 7 x + 10 = 1 - x

\frac{x}{2} - 2 x = - 9

- \frac{1}{2} x \leq \frac{- 3}{4} + \frac{2}{5} x

What are the solutions to the equation 10^2+11^2=x^2 ?
The solutions to the equation 10^2+11^2=x^2 are x=sqrt(221),x=-sqrt(221)
Find the zeros of 10^2+11^2=x^2
The zeros of 10^2+11^2=x^2 are x=sqrt(221),x=-sqrt(221)