What is the answer to |x^2-4|=1 ?

The answer to |x^2-4|=1 is x=-sqrt(5)\lor x=-sqrt(3)\lor x=sqrt(3)\lor x=sqrt(5)

Solve for x: |x^2-4|=1

The solution is x=-sqrt(5)\lor x=-sqrt(3)\lor x=sqrt(3)\lor x=sqrt(5)

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x^{2} - 4 = 1

x = - 5 or x = - 3 or x = 3 or x = 5

Decimal Notation

x = - 2.23606 \dots, x = - 1.73205 \dots, x = 1.73205 \dots, x = 2.23606 \dots

Solution steps

x^{2} - 4 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 = - 1 or x^{2} - 4 = 1

x^{2} - 4 = - 1 or x^{2} - 4 = 1

(x = - 3 or x = 3) or (x = - 5 or x = 5)

x = - 5 or x = - 3 or x = 3 or x = 5

f = 6^{1}

(x - 4) (x + 2)^{2} \leq 0

- 36 = \frac{x}{2}

4 b^{2} + 28 b + 4

2 (3 x + 4) + 6 (4 x + 4) + 6 = 30 x + 39

What is the answer to |x^2-4|=1 ?
The answer to |x^2-4|=1 is x=-sqrt(5)\lor x=-sqrt(3)\lor x=sqrt(3)\lor x=sqrt(5)
Solve for x: |x^2-4|=1
The solution is x=-sqrt(5)\lor x=-sqrt(3)\lor x=sqrt(3)\lor x=sqrt(5)