What is the answer to (x-7)/5-(x-11)/6+(x-10)/7 =2 ?

The answer to (x-7)/5-(x-11)/6+(x-10)/7 =2 is x=17

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(x-7)/5-(x-11)/6+(x-10)/7 =2

\frac{x - 7}{5} - \frac{x - 11}{6} + \frac{x - 10}{7} = 2

x = 17

Solution steps

\frac{x - 7}{5} - \frac{x - 11}{6} + \frac{x - 10}{7} = 2

Multiply by LCM

42 (x - 7) - 35 (x - 11) + 30 (x - 10) = 420

Expand

42 (x - 7) - 35 (x - 11) + 30 (x - 10) : 37 x - 209

37 x - 209 = 420

Move

209

to the right side

37 x = 629

Divide both sides by

37

x = 17

- 6 \leq x \leq 6

\frac{2}{p ^{2} + pq} + \frac{3}{pq - q ^{2}}

\frac{2}{x} \frac{5}{y}

3 r^{2} + 8 r + 5

3 X - 5 < \frac{3}{4} X + \frac{( 1 - X )}{3}

What is the answer to (x-7)/5-(x-11)/6+(x-10)/7 =2 ?
The answer to (x-7)/5-(x-11)/6+(x-10)/7 =2 is x=17
Solve for x: (x-7)/5-(x-11)/6+(x-10)/7 =2
The solution is x=17