What is factor e^{2+4i} ?

The solution to factor e^{2+4i} is e^2cos(4)+e^2isin(4)

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factor e^{2+4i}

factor

e^{2 + 4 i}

e^{2} cos (4) + e^{2} i sin (4)

Solution steps

e^{2 + 4 i}

Apply imaginary number rule:

e^{a + ib} = e^{a} (cos (b) + i sin (b))

= e^{2} (cos (4) + i sin (4))

Rewrite

e^{2} (cos (4) + sin (4) i)

in standard complex form:

e^{2} cos (4) + e^{2} sin (4) i

= e^{2} cos (4) + e^{2} sin (4) i

(5)^{2}

7 r^{3} - 35 r^{2} + 6 r - 30

∣ x - 7 ∣ = 1

- 2 + \frac{3}{2}

x^{2} + 16 x + 60 = 0

What is factor e^{2+4i} ?
The solution to factor e^{2+4i} is e^2cos(4)+e^2isin(4)