What is (\frac{-2x)/(x-y)}{y/(x^2)} ?

The solution to (\frac{-2x)/(x-y)}{y/(x^2)} is -(2x^3)/((x-y)y)

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simplify (\frac{-2x)/(x-y)}{y/(x^2)}

simplify

\frac{\frac{- 2 x}{x - y}}{\frac{y}{x ^{2}}}

- \frac{2 x ^{3}}{( x - y ) y}

Solution steps

\frac{\frac{- 2 x}{x - y}}{\frac{y}{x ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{- 2 x x ^{2}}{( x - y ) y}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2 x x ^{2}}{( x - y ) y}

Simplify

x x^{2} : x^{3}

= - \frac{2 x ^{3}}{( x - y ) y}

125

\frac{x ^{\frac{1}{2}}}{x ^{\frac{3}{4}}}

\frac{5 x - 1}{3} + 2 \leq \frac{x + 4}{7}

5 x - 9 = - 3 x + 7

x (x + 2) \leq 0

What is (\frac{-2x)/(x-y)}{y/(x^2)} ?
The solution to (\frac{-2x)/(x-y)}{y/(x^2)} is -(2x^3)/((x-y)y)