What are the solutions to the equation 0=s^2+4s+5 ?

The solutions to the equation 0=s^2+4s+5 are s=-2+i,s=-2-i

Find the zeros of 0=s^2+4s+5

The zeros of 0=s^2+4s+5 are s=-2+i,s=-2-i

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0 = s^{2} + 4 s + 5

s = - 2 + i, s = - 2 - i

Solution steps

0 = s^{2} + 4 s + 5

Switch sides

s^{2} + 4 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

s_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, s_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

s = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

s = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

s = - 2 + i, s = - 2 - i

x + x + (x + 18) = 180

\frac{1 0 ^{2}}{2} - \frac{4 ^{2}}{2} - 6

0.1 (x + 7) = 3.5

\frac{x}{- 9} + 3 > 10

\frac{6 a ^{5} b ^{7}}{- 2 a ^{3} b ^{7}}

What are the solutions to the equation 0=s^2+4s+5 ?
The solutions to the equation 0=s^2+4s+5 are s=-2+i,s=-2-i
Find the zeros of 0=s^2+4s+5
The zeros of 0=s^2+4s+5 are s=-2+i,s=-2-i