What is the answer to (3x-1)^2-(5x-3)^2=-(4x-2)^2 ?

The answer to (3x-1)^2-(5x-3)^2=-(4x-2)^2 is x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3x-1)^2-(5x-3)^2=-(4x-2)^2

(3 x - 1)^{2} - (5 x - 3)^{2} = - (4 x - 2)^{2}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

(3 x - 1)^{2} - (5 x - 3)^{2} = - (4 x - 2)^{2}

Expand

(3 x - 1)^{2} - (5 x - 3)^{2} : - 16 x^{2} + 24 x - 8

Expand

- (4 x - 2)^{2} : - 16 x^{2} + 16 x - 4

- 16 x^{2} + 24 x - 8 = - 16 x^{2} + 16 x - 4

Move

8

to the right side

- 16 x^{2} + 24 x = - 16 x^{2} + 16 x + 4

Subtract

- 16 x^{2} + 16 x

from both sides

- 16 x^{2} + 24 x - (- 16 x^{2} + 16 x) = - 16 x^{2} + 16 x + 4 - (- 16 x^{2} + 16 x)

Simplify

8 x = 4

Divide both sides by

8

x = \frac{1}{2}

6 z^{2} - 27 z + 30

3 x + 12 = \frac{x + 3}{3}

(3 x^{2} - 12 x) (x^{2} - 2 x + 1)

4 x^{2} - 8 x - 3 = 0

x^{2} + 9 x = 14

What is the answer to (3x-1)^2-(5x-3)^2=-(4x-2)^2 ?
The answer to (3x-1)^2-(5x-3)^2=-(4x-2)^2 is x= 1/2
Solve for x: (3x-1)^2-(5x-3)^2=-(4x-2)^2
The solution is x= 1/2